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p^2-430p-104.000=0
We add all the numbers together, and all the variables
p^2-430p-104=0
a = 1; b = -430; c = -104;
Δ = b2-4ac
Δ = -4302-4·1·(-104)
Δ = 185316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{185316}=\sqrt{4*46329}=\sqrt{4}*\sqrt{46329}=2\sqrt{46329}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-430)-2\sqrt{46329}}{2*1}=\frac{430-2\sqrt{46329}}{2} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-430)+2\sqrt{46329}}{2*1}=\frac{430+2\sqrt{46329}}{2} $
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